I have calculated probabilities · More Probabilities · The Bases of the Probabilities
If you have 26 letters, and if you add these to each other, how many possibilities do you have for numeric outcomes?
First combination of two is, A + A = 2 (in "gematria by 1") or 2+2*64 = 130 in ASCII. Next combination of two is value 3 or rather 131, you have two possibilities, either AB or BA. Midway you will have 26 possibilities for AZ, MN, NM, ZA and so on. At ZZ you are down to one sole possibility for 180, again.
1 | 130 | 180 | ||
2 | 131 | 179 | ||
3 | 132 | 178 | ||
4 | 133 | 177 | ||
5 | 134 | 176 | ||
6 | 135 | 175 | ||
7 | 136 | 174 | ||
8 | 137 | 173 | ||
9 | 138 | 172 | ||
10 | 139 | 171 | ||
11 | 140 | 170 | ||
12 | 141 | 169 | ||
13 | 142 | 168 | ||
14 | 143 | 167 | ||
15 | 144 | 166 | ||
16 | 145 | 165 | ||
17 | 146 | 164 | ||
18 | 147 | 163 | ||
19 | 148 | 162 | ||
20 | 149 | 161 | ||
21 | 150 | 160 | ||
22 | 151 | 159 | ||
23 | 152 | 158 | ||
24 | 153 | 157 | ||
25 | 154 | 156 | ||
26 | 155 |
First combination of three is, A+A+A = 3 or rather 3+3*64 = 195. It's one only. Next, 196, has three possibilities, AAB, ABA, BAA. One, then three, seems like triangle numbers? Well, yes, to a point.
You cannot get higher in triangle numbers than 1+2+3 ... +26, that is 351. Because next value will also only have 26 possibilities, like one for each letter of the third, and to the former two the diverse combinations, ranging from 2 to 26, which makes 25 of the letters, and then 25 only for Z. Next after that will have 3 to 26, then 25 for Y and 24 for Z. And so on.
Now, if triangle number of 26 is 351, next value will be 351 - 1 + 25, which is 375. Next value after that will be 375 - 2 + 24, which is 397. You may notice that if first after triangle numbers differs by - 1 + 25, it differs concretely by + 24. Next differs by - 2 + 24, concretely by + 22. This means, the values get higher and higher, but by decreasing increments, up to 501 + 4 = 505, 505 + 2 = 507. And after that, next one is also 507, then 505, 501 and back to 351 and the triangle numbers down to 1.
Here are he triangle numbers part, increasing from 1 for 195 and then decreasing to 1 for 270:
1 | 195 | 270 | ||
3 | 196 | 269 | ||
6 | 197 | 268 | ||
10 | 198 | 267 | ||
15 | 199 | 266 | ||
21 | 200 | 265 | ||
28 | 201 | 264 | ||
36 | 202 | 263 | ||
45 | 203 | 262 | ||
55 | 204 | 261 | ||
66 | 205 | 260 | ||
78 | 206 | 259 | ||
91 | 207 | 258 | ||
105 | 208 | 257 | ||
120 | 209 | 256 | ||
136 | 210 | 255 | ||
153 | 211 | 254 | ||
171 | 212 | 253 | ||
190 | 213 | 252 | ||
210 | 214 | 251 | ||
231 | 215 | 250 | ||
253 | 216 | 249 | ||
276 | 217 | 248 | ||
300 | 218 | 247 | ||
325 | 219 | 246 | ||
351 | 220 | 245 |
So far triangle numbers, and now for decreassing increments:
375 | 221 | 244 | ||
397 | 222 | 243 | ||
417 | 223 | 242 | ||
435 | 224 | 241 | ||
451 | 225 | 240 | ||
465 | 226 | 239 | ||
477 | 227 | 238 | ||
487 | 228 | 237 | ||
495 | 229 | 236 | ||
501 | 230 | 235 | ||
505 | 231 | 234 | ||
507 | 232 | 233 |
Any combination of three upper case letters of the normal English alphabet will be between 195 and 270, and its probability will be between 1 possibility for each of these two to 507 possibilities for each of 232 and 233.
Note, it is impossible to know how many of the letter combinations give meaning in any language and how many of those adding up to a particular number give meaning in any one. But the proportions in all combinations including gibberish will indicate something about the proportions in meaningful combinations.
Hans Georg Lundahl
Cergy
St. Nicolas of Tolentino
10.IX.2019
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