George F.R. Ellis was on FB quoted as saying or writing some time in the past (I'll try to contact him to see if the quote is genuine):
I can construct you a spherically symmetrical universe with Earth at its center*, and you cannot disprove it based on observations. You can only exclude it on philosophical grounds...we are using philosophical criteria in choosing our models. A lot of csmology tries to hide that.
On a more humdrum level ... I was discussing whether the scientists who are constructing an Earth orbitting around the Sun by the interplay of two forces, gravitation as centripetal one and tangential inertia as centrifugal one can have missed factors which would make this possible.
It was on theologyweb, and when I tried to just browse the previous discussion this morning, I saw this:
500 - Internal Server Error
So, I'll have to discuss this a bit on my own, before my readers ...
Mean orbital velocity (km/s) 29.78 **
Max. orbital velocity (km/s) 30.29
Min. orbital velocity (km/s) 29.29
Mass (1024 kg) 5.9723**
I had in that debate been told that the "dust" which hits Earth on a "daily basis" is 200 tons***.
I was asking - before this blackout 500 error - whether meteors dissolving in the atmosphere or hitting ground during the annual meteor showers was a myth, or if not included or excluded from the 200 tons of dust.
The other guy had been counting on my backing down very quickly on seeing the results he had allowed me to calculate on his terms, and was perhaps not ready for my challenging the terms with things that imply one should take a few more things into account too.
I didn't do quite what he had counted on. Your guess, if that has anything to do with the 500 error or not.
Also, the 200 tons, I am here presuming that is what is hitting Earth. In the orbit of Earth around Sun (or supposed such) it is also a question of how much is hitting the Moon. Since Moon too is involved in Earth's orbit around Earth.
Earth has a Volumetric mean radius of (km) 6371.008.
Moon° has a Volumetric mean radius of (km) 1737.4
The volumetric mean radii are given as compared:
Volumetric mean radius (km) (Moon) 1737.4 (Earth) 6371.0 (Moon/Earth ratio) 0.2727
I'll now take the Moon/Earth ratio, square it, since Earth and Moon are both hovering by space (supposedly) and hitting space from an angle describing a circle which has a surface proportional to the tens that hit it.
0.2727*0.2727 = 0.07436529.
So, Moon has an added 0,07436529 of the surface. 1 + 0.07436529 = 1.07436529
This means the tons are more like 214 873.058 than like 200 000 kg.
On the other hand, they should be added to a larger mass, Earth and Moon = Mass° (1024 kg) 0.07346+5.9724=6.04586 (1024 kg).
I am not here sure whether the 200 tons include or exclude what confronts the ring of the 8.5 km atmospheric height around the 6371.008 km around midpoint, and due to gravitation, a meteor or even dustparticle which comes outside the 8.5 km limit will perhaps also be sucked in. On the other hand, sometimes Moon is before or after Earth in orbit, and so is getting or leaving no extra, but only one gets the dust? If so, this might even out.
Should this be added to the 200 tons per day, or should it be considered as already included in them? I'll go with the latter one. If it is the former, you ask someone else, and add this to the problem.
Also, I think someone else might have to ask whether the 200 tons dust per day are also including or more probably excluding the Perseid and Aquariid meteor showers in August.
I'll just calculate for the dust.
Now, I made a mistake in relation to translating the 1024 kg to correct number of zeros.
000 000 (add six zeros)
000 000 (another six = 12 zeros)
000 000 (18 zeros)
000 000 (24 zeros)
1 000 000 000 000 000 000 000 000
Let's get going.
6.045 86 *
1 000 000 000 000 000 000 000 000
= 6 045 860,000,000,000,000,000,000 kg present mass
214 873.058 * 365.2425 * 4 500 000 000 (years in which Earth has supposedly been in orbit, projected into future):
353 163 477 989 542 500 kg added mass.
Added to what? To 6 045 860 000 000 000 000 000 000 kg of Earth and Moon.
= 6 045 860 353 163 477 989 542 500 kg new mass
Ratio : 1.000,000,058,414,101,2
This well also be the ratio of changing gravitation from Sun, since gravitation is directly proportional on mass.
Now, the kgm/s of Earth+Moon is for present Mass:
6 045 860 000 000 000 000 000 000 kg * 29 785 m/s = 180 075 940 100 000 000 000 000 000 000 kgm/s
Each day what is deducted is same speed times the 214 873.058 kg.
214 873.058*29785 = 6 399 994 032.53
6 399 994 032.53 * 365,2425 * 4 500 000 000 = 10 518 974 191 918 523 362 500 kgm/s
180 075 940 100 000 000 000 000 000 000 - 10 518 974 191 918 523 362 500 kgm/s = 180 075 929 581 025 808 081 476 637 500 kgm/s
Ratio present to new : 0.9999999415858988
So, in 4.5 billion years, kgm/s lowers to 0.999,999,941,585,898,8 of original, and gravitational pull from Sun rises to 1.000,000,058,414,101,2 of original.
Shall we just try to consider them as at present "in balance" 1:1 and check the imbalance?
1:1 - > 1.0000001168282092244:1 = for the gravitational pull against tangential momentum of Earth and Moon.
Or 10 000 001 168 282 092 244:10 000 000 000 000 000 000.
Or 10 000 001:10 000 000.
I am now presuming speed as such is irrelevant, it is just momentum vs gravitation.
But what if speed does count?
New momentum : 180 075 929 581 025 808 081 476 637 500 kgm/s
New mass : 6 045 860 353 163 477 989 542 500 kg
Momentum/mass = m/s (kgm/kgs=
New speed : 29 784.996,520,272,193,712 m/s.
The average velocity change is therefore about 3 mm/s lower on near 30 km/s.
But let's suppose that the velocity and the gravitation from Sun are a 1:1 balance, and see where the balance goes, if it is speed instead of momentum which needs to balance gravitation?
29 784.996,520,272,193,712 m/s / 29785 m/s = 0.999,999,883,171,804,389
So balance gravitation:speed shifts from 1:1 to
1.000,000,058,414,101,2:0.999,999,883,171,804,389 = 1.000,000,175,242,317,284,244:1
Or 1 000 000 175 242 317 284 244:1 000 000 000 000 000 000 000
Or 10 000 002:10 000 000.
So, the shifting balance, probably discounting all meteor showers, would be 1:1 to 10 000 001:10 000 000 in gravitation:momentum or, in gravitation:speed, it would shift to 10 000 002:10 000 000.
Now, while this is certainly insignificant, I don't know enough physics to determine whether a balance of 10 000 001:10 000 000 in gravitation:momentum or a balance of 10 000 002:10 000 000 in gravitation:speed can work.
I don't know how many orbits such an imbalance can take before toppling over. Ten million, perhaps? Or perhaps a bit more than five million, if we take second imbalance?
Remember, I have now only calculated from present rates forward, 4.5 billion years into the future. We are supposed to have already 4.5 billion years behind us. With an initial imbalance that size, we would not have lasted 4.5 billion years. With an initial balance, we would already have an imbalance about that size.
So, we could perhaps predict that Earth has perhaps only ten million years to go?
But ten million years ago, was 4.49 billion years from start. With nearly same imbalance. So, we should be gone any moment. 15 million years ago was 4.485 billion years from start. With nearly same imbalance. So we should already be gone.
Or, the Newtonian and Evolutionistic (large sense) view of Earth's rotation around the Sun might NOT be correct, Earth might be in centre of Universe, and Sun be ceasing to rotate anytime God wants, but not one nanosecond before that. That is what I think makes sense.
But hey guys, why take my word for it? One debater (not on that forum, but on youtube) told me I should remove my possibilities of procreation, and another I should take my meds, but was lobotomised by a rusty saw instead of proper equipment. So, do the math yourself. And, if in a sane moment I see your comment as correcting mine, I'll be happy to let it stay there.
Or I might try to see any faults there could be with your maths too ...
Or, more importantly, the suppositions behind them.
Hans Georg Lundahl
Abbot St Euthymius°°
Credits for all actual calculations (multiplications, divisions, additions, subtractions) to http://web2.0calc.fr/
Credits to oxmixmudd on theologyweb for giving me a setup of initial calculations, somewhat differing from these. Obviously, I "suffer from" severe Dunning Kruger for thinking the parameters I took into account as being finally more relevant than his, but nevertheless, he gave me the model I am imagining to have corrected for relevance to the supposed physical reality of Heliocentrism.
* No doubt American spelling for centre.
*** I presume he meant metric ones, 1000 kg each?
°° Last saint of today : In Palaestina natalis sancti Euthymii Abbatis, qui zelo catholicae disciplinae et virtute miraculorum, tempore Marciani Imperatoris, in Ecclesia floruit.
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Otherwise I was going to try to bring this home to oxmixmudd, well, must wait ...
Update on theologyweb :
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We were doing a needed OS upgrade and were up for a bit, but we've gone down again. Too many things were having issues with upgrading to php7 (which was needed as Ubuntu 16.04 LTS doesn't play with php5). I am just downloading a db backup (10GB) and and then will be restoring to the previous version and then restoring the database. We'll leave the OS update to happen when we update vBulletin (on the roadmap for later this year)
We will be back soon...